29 lines
881 B
Python
29 lines
881 B
Python
import pandas as pd
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# 读取Excel文件
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file_path = '/Users/a123/Documents/UthinkJava2025/xbb-api-demo/sql/名称代码对应表.xls'
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df = pd.read_excel(file_path)
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# 打印列名
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print("列名:")
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for i, col in enumerate(df.columns):
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print(f"{i+1}. {col}")
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# 打印前几行数据
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print("\n前5行数据:")
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print(df.head())
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# 构建替换映射数组
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name_code_map = []
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for index, row in df.iterrows():
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# 假设第一列是名称，第二列是代码
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if len(df.columns) >= 2:
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name = str(row.iloc[0]) if not pd.isna(row.iloc[0]) else ''
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code = str(row.iloc[1]) if not pd.isna(row.iloc[1]) else ''
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if name and code:
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name_code_map.append((name, code))
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print("\n名称代码对应关系:")
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for name, code in name_code_map[:10]: # 只打印前10个
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print(f"{name} -> {code}")
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print(f"总共 {len(name_code_map)} 个映射关系") |